((5^0a^7b^-3c^5)/(a^10b^4c))^-2

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Solution for ((5^0a^7b^-3c^5)/(a^10b^4c))^-2 equation: 


D( x )

a^10*b^4*c = 0

(5^0*a^7*b^-3*c^5)/(a^10*b^4*c) = 0

a^10*b^4*c = 0

a^10*b^4*c = 0

a^10*b^4*c = 0

x należy do R

(5^0*a^7*b^-3*c^5)/(a^10*b^4*c) = 0

(5^0*a^7*b^-3*c^5)/(a^10*b^4*c) = 0

(a^7*b^-3*c^5)/(a^10*b^4*c) = 0

a^-3*b^-7*c^4 = 0

x należy do R

x belongs to the empty set

((5^0*a^7*b^-3*c^5)/(a^10*b^4*c))^-2 = 0

x belongs to the empty set

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